Here we will use algebra to find three consecutive integers whose sum is 233. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 233. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 233
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 233
3X + 3 = 233
3X + 3 - 3 = 233 - 3
3X = 230
3X/3 = 230/3
X = 76 2/3
Since 76 2/3 is not an integer, there is no true answer to this problem.
However, there are three numbers that add up to 233. The first number is (76 2/3), the second number is (76 2/3) + 1, and the third number is (76 2/3) + 2. Therefore, we could make this the answer to "Three consecutive numbers that add up to 233 are?":
76 2/3 + 77 2/3 + 78 2/3 = 233
Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.
What three consecutive integers have a sum of 234?
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