Here we will use algebra to find three consecutive integers whose sum is 856. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 856. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 856
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 856
3X + 3 = 856
3X + 3 - 3 = 856 - 3
3X = 853
3X/3 = 853/3
X = 284 1/3
Since 284 1/3 is not an integer, there is no true answer to this problem.
However, there are three numbers that add up to 856. The first number is (284 1/3), the second number is (284 1/3) + 1, and the third number is (284 1/3) + 2. Therefore, we could make this the answer to "Three consecutive numbers that add up to 856 are?":
284 1/3 + 285 1/3 + 286 1/3 = 856
Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.
What three consecutive integers have a sum of 857?
Here is the next algebra problem we solved.
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