What three consecutive integers have a sum of 888?

Here we will use algebra to find three consecutive integers whose sum is 888. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 888. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 888

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 888
3X + 3 = 888

3X + 3 - 3 = 888 - 3
3X = 885

3X/3 = 885/3
X = 295

Which means that the first number is 295, the second number is 295 + 1 and the third number is 295 + 2. Therefore, three consecutive integers that add up to 888 are 295, 296, and 297.

295 + 296 + 297 = 888

We know our answer is correct because 295 + 296 + 297 equals 888 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 889?
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