Here we will use algebra to find three consecutive integers whose sum is 912. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 912. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 912
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 912
3X + 3 = 912
3X + 3 - 3 = 912 - 3
3X = 909
3X/3 = 909/3
X = 303
Which means that the first number is 303, the second number is 303 + 1 and the third number is 303 + 2. Therefore, three consecutive integers that add up to 912 are 303, 304, and 305.
303 + 304 + 305 = 912
We know our answer is correct because 303 + 304 + 305 equals 912 as displayed above.
Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.
What three consecutive integers have a sum of 913?
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