What three consecutive integers have a sum of 933?




Here we will use algebra to find three consecutive integers whose sum is 933. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 933. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 933


To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 933
3X + 3 = 933

3X + 3 - 3 = 933 - 3
3X = 930

3X/3 = 930/3
X = 310

Which means that the first number is 310, the second number is 310 + 1 and the third number is 310 + 2. Therefore, three consecutive integers that add up to 933 are 310, 311, and 312.

310 + 311 + 312 = 933

We know our answer is correct because 310 + 311 + 312 equals 933 as displayed above.


Three Consecutive Integers
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What three consecutive integers have a sum of 934?
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