What three consecutive integers have a sum of 1010?

Here we will use algebra to find three consecutive integers whose sum is 1010. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 1010. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 1010

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 1010
3X + 3 = 1010

3X + 3 - 3 = 1010 - 3
3X = 1007

3X/3 = 1007/3
X = 335 2/3

Since 335 2/3 is not an integer, there is no true answer to this problem.

However, there are three numbers that add up to 1010. The first number is (335 2/3), the second number is (335 2/3) + 1, and the third number is (335 2/3) + 2. Therefore, we could make this the answer to "Three consecutive numbers that add up to 1010 are?":

335 2/3 + 336 2/3 + 337 2/3 = 1010

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 1011?
Here is the next algebra problem we solved.