What three consecutive integers have a sum of 102?

Here we will use algebra to find three consecutive integers whose sum is 102. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 102. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 102

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 102
3X + 3 = 102

3X + 3 - 3 = 102 - 3
3X = 99

3X/3 = 99/3
X = 33

Which means that the first number is 33, the second number is 33 + 1 and the third number is 33 + 2. Therefore, three consecutive integers that add up to 102 are 33, 34, and 35.

33 + 34 + 35 = 102

We know our answer is correct because 33 + 34 + 35 equals 102 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 103?
Here is the next algebra problem we solved.