What three consecutive integers have a sum of 1056?

Here we will use algebra to find three consecutive integers whose sum is 1056. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 1056. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 1056

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 1056
3X + 3 = 1056

3X + 3 - 3 = 1056 - 3
3X = 1053

3X/3 = 1053/3
X = 351

Which means that the first number is 351, the second number is 351 + 1 and the third number is 351 + 2. Therefore, three consecutive integers that add up to 1056 are 351, 352, and 353.

351 + 352 + 353 = 1056

We know our answer is correct because 351 + 352 + 353 equals 1056 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 1057?
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