What three consecutive integers have a sum of 1101?

Here we will use algebra to find three consecutive integers whose sum is 1101. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 1101. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 1101

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 1101
3X + 3 = 1101

3X + 3 - 3 = 1101 - 3
3X = 1098

3X/3 = 1098/3
X = 366

Which means that the first number is 366, the second number is 366 + 1 and the third number is 366 + 2. Therefore, three consecutive integers that add up to 1101 are 366, 367, and 368.

366 + 367 + 368 = 1101

We know our answer is correct because 366 + 367 + 368 equals 1101 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 1102?
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