What three consecutive integers have a sum of 1125?

Here we will use algebra to find three consecutive integers whose sum is 1125. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 1125. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 1125

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 1125
3X + 3 = 1125

3X + 3 - 3 = 1125 - 3
3X = 1122

3X/3 = 1122/3
X = 374

Which means that the first number is 374, the second number is 374 + 1 and the third number is 374 + 2. Therefore, three consecutive integers that add up to 1125 are 374, 375, and 376.

374 + 375 + 376 = 1125

We know our answer is correct because 374 + 375 + 376 equals 1125 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 1126?
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