What three consecutive integers have a sum of 1230?

Here we will use algebra to find three consecutive integers whose sum is 1230. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 1230. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 1230

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 1230
3X + 3 = 1230

3X + 3 - 3 = 1230 - 3
3X = 1227

3X/3 = 1227/3
X = 409

Which means that the first number is 409, the second number is 409 + 1 and the third number is 409 + 2. Therefore, three consecutive integers that add up to 1230 are 409, 410, and 411.

409 + 410 + 411 = 1230

We know our answer is correct because 409 + 410 + 411 equals 1230 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 1231?
Here is the next algebra problem we solved.