What three consecutive integers have a sum of 1401?

Here we will use algebra to find three consecutive integers whose sum is 1401. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 1401. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 1401

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 1401
3X + 3 = 1401

3X + 3 - 3 = 1401 - 3
3X = 1398

3X/3 = 1398/3
X = 466

Which means that the first number is 466, the second number is 466 + 1 and the third number is 466 + 2. Therefore, three consecutive integers that add up to 1401 are 466, 467, and 468.

466 + 467 + 468 = 1401

We know our answer is correct because 466 + 467 + 468 equals 1401 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 1402?
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