What three consecutive integers have a sum of 1920?

Here we will use algebra to find three consecutive integers whose sum is 1920. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 1920. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 1920

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 1920
3X + 3 = 1920

3X + 3 - 3 = 1920 - 3
3X = 1917

3X/3 = 1917/3
X = 639

Which means that the first number is 639, the second number is 639 + 1 and the third number is 639 + 2. Therefore, three consecutive integers that add up to 1920 are 639, 640, and 641.

639 + 640 + 641 = 1920

We know our answer is correct because 639 + 640 + 641 equals 1920 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 1921?
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