What three consecutive integers have a sum of 1956?

Here we will use algebra to find three consecutive integers whose sum is 1956. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 1956. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 1956

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 1956
3X + 3 = 1956

3X + 3 - 3 = 1956 - 3
3X = 1953

3X/3 = 1953/3
X = 651

Which means that the first number is 651, the second number is 651 + 1 and the third number is 651 + 2. Therefore, three consecutive integers that add up to 1956 are 651, 652, and 653.

651 + 652 + 653 = 1956

We know our answer is correct because 651 + 652 + 653 equals 1956 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 1957?
Here is the next algebra problem we solved.