What three consecutive integers have a sum of 2157?

Here we will use algebra to find three consecutive integers whose sum is 2157. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 2157. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 2157

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 2157
3X + 3 = 2157

3X + 3 - 3 = 2157 - 3
3X = 2154

3X/3 = 2154/3
X = 718

Which means that the first number is 718, the second number is 718 + 1 and the third number is 718 + 2. Therefore, three consecutive integers that add up to 2157 are 718, 719, and 720.

718 + 719 + 720 = 2157

We know our answer is correct because 718 + 719 + 720 equals 2157 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 2158?
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