What three consecutive integers have a sum of 2232?

Here we will use algebra to find three consecutive integers whose sum is 2232. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 2232. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 2232

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 2232
3X + 3 = 2232

3X + 3 - 3 = 2232 - 3
3X = 2229

3X/3 = 2229/3
X = 743

Which means that the first number is 743, the second number is 743 + 1 and the third number is 743 + 2. Therefore, three consecutive integers that add up to 2232 are 743, 744, and 745.

743 + 744 + 745 = 2232

We know our answer is correct because 743 + 744 + 745 equals 2232 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 2233?
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