What three consecutive integers have a sum of 2316?

Here we will use algebra to find three consecutive integers whose sum is 2316. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 2316. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 2316

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 2316
3X + 3 = 2316

3X + 3 - 3 = 2316 - 3
3X = 2313

3X/3 = 2313/3
X = 771

Which means that the first number is 771, the second number is 771 + 1 and the third number is 771 + 2. Therefore, three consecutive integers that add up to 2316 are 771, 772, and 773.

771 + 772 + 773 = 2316

We know our answer is correct because 771 + 772 + 773 equals 2316 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 2317?
Here is the next algebra problem we solved.