What three consecutive integers have a sum of 2472?

Here we will use algebra to find three consecutive integers whose sum is 2472. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 2472. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 2472

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 2472
3X + 3 = 2472

3X + 3 - 3 = 2472 - 3
3X = 2469

3X/3 = 2469/3
X = 823

Which means that the first number is 823, the second number is 823 + 1 and the third number is 823 + 2. Therefore, three consecutive integers that add up to 2472 are 823, 824, and 825.

823 + 824 + 825 = 2472

We know our answer is correct because 823 + 824 + 825 equals 2472 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 2473?
Here is the next algebra problem we solved.