What three consecutive integers have a sum of 2520?

Here we will use algebra to find three consecutive integers whose sum is 2520. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 2520. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 2520

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 2520
3X + 3 = 2520

3X + 3 - 3 = 2520 - 3
3X = 2517

3X/3 = 2517/3
X = 839

Which means that the first number is 839, the second number is 839 + 1 and the third number is 839 + 2. Therefore, three consecutive integers that add up to 2520 are 839, 840, and 841.

839 + 840 + 841 = 2520

We know our answer is correct because 839 + 840 + 841 equals 2520 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 2521?
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