What three consecutive integers have a sum of 2622?

Here we will use algebra to find three consecutive integers whose sum is 2622. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 2622. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 2622

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 2622
3X + 3 = 2622

3X + 3 - 3 = 2622 - 3
3X = 2619

3X/3 = 2619/3
X = 873

Which means that the first number is 873, the second number is 873 + 1 and the third number is 873 + 2. Therefore, three consecutive integers that add up to 2622 are 873, 874, and 875.

873 + 874 + 875 = 2622

We know our answer is correct because 873 + 874 + 875 equals 2622 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 2623?
Here is the next algebra problem we solved.