What three consecutive integers have a sum of 2628?

Here we will use algebra to find three consecutive integers whose sum is 2628. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 2628. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 2628

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 2628
3X + 3 = 2628

3X + 3 - 3 = 2628 - 3
3X = 2625

3X/3 = 2625/3
X = 875

Which means that the first number is 875, the second number is 875 + 1 and the third number is 875 + 2. Therefore, three consecutive integers that add up to 2628 are 875, 876, and 877.

875 + 876 + 877 = 2628

We know our answer is correct because 875 + 876 + 877 equals 2628 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 2629?
Here is the next algebra problem we solved.