What three consecutive integers have a sum of 2838?

Here we will use algebra to find three consecutive integers whose sum is 2838. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 2838. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 2838

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 2838
3X + 3 = 2838

3X + 3 - 3 = 2838 - 3
3X = 2835

3X/3 = 2835/3
X = 945

Which means that the first number is 945, the second number is 945 + 1 and the third number is 945 + 2. Therefore, three consecutive integers that add up to 2838 are 945, 946, and 947.

945 + 946 + 947 = 2838

We know our answer is correct because 945 + 946 + 947 equals 2838 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 2839?
Here is the next algebra problem we solved.