What three consecutive integers have a sum of 3009?

Here we will use algebra to find three consecutive integers whose sum is 3009. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 3009. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 3009

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 3009
3X + 3 = 3009

3X + 3 - 3 = 3009 - 3
3X = 3006

3X/3 = 3006/3
X = 1002

Which means that the first number is 1002, the second number is 1002 + 1 and the third number is 1002 + 2. Therefore, three consecutive integers that add up to 3009 are 1002, 1003, and 1004.

1002 + 1003 + 1004 = 3009

We know our answer is correct because 1002 + 1003 + 1004 equals 3009 as displayed above.

Three Consecutive Integers
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