What three consecutive integers have a sum of 3015?

Here we will use algebra to find three consecutive integers whose sum is 3015. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 3015. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 3015

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 3015
3X + 3 = 3015

3X + 3 - 3 = 3015 - 3
3X = 3012

3X/3 = 3012/3
X = 1004

Which means that the first number is 1004, the second number is 1004 + 1 and the third number is 1004 + 2. Therefore, three consecutive integers that add up to 3015 are 1004, 1005, and 1006.

1004 + 1005 + 1006 = 3015

We know our answer is correct because 1004 + 1005 + 1006 equals 3015 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 3016?
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