What three consecutive integers have a sum of 3033?

Here we will use algebra to find three consecutive integers whose sum is 3033. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 3033. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 3033

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 3033
3X + 3 = 3033

3X + 3 - 3 = 3033 - 3
3X = 3030

3X/3 = 3030/3
X = 1010

Which means that the first number is 1010, the second number is 1010 + 1 and the third number is 1010 + 2. Therefore, three consecutive integers that add up to 3033 are 1010, 1011, and 1012.

1010 + 1011 + 1012 = 3033

We know our answer is correct because 1010 + 1011 + 1012 equals 3033 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 3034?
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