What three consecutive integers have a sum of 3240?

Here we will use algebra to find three consecutive integers whose sum is 3240. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 3240. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 3240

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 3240
3X + 3 = 3240

3X + 3 - 3 = 3240 - 3
3X = 3237

3X/3 = 3237/3
X = 1079

Which means that the first number is 1079, the second number is 1079 + 1 and the third number is 1079 + 2. Therefore, three consecutive integers that add up to 3240 are 1079, 1080, and 1081.

1079 + 1080 + 1081 = 3240

We know our answer is correct because 1079 + 1080 + 1081 equals 3240 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 3241?
Here is the next algebra problem we solved.