What three consecutive integers have a sum of 3330?

Here we will use algebra to find three consecutive integers whose sum is 3330. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 3330. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 3330

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 3330
3X + 3 = 3330

3X + 3 - 3 = 3330 - 3
3X = 3327

3X/3 = 3327/3
X = 1109

Which means that the first number is 1109, the second number is 1109 + 1 and the third number is 1109 + 2. Therefore, three consecutive integers that add up to 3330 are 1109, 1110, and 1111.

1109 + 1110 + 1111 = 3330

We know our answer is correct because 1109 + 1110 + 1111 equals 3330 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 3331?
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