What three consecutive integers have a sum of 3564?

Here we will use algebra to find three consecutive integers whose sum is 3564. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 3564. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 3564

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 3564
3X + 3 = 3564

3X + 3 - 3 = 3564 - 3
3X = 3561

3X/3 = 3561/3
X = 1187

Which means that the first number is 1187, the second number is 1187 + 1 and the third number is 1187 + 2. Therefore, three consecutive integers that add up to 3564 are 1187, 1188, and 1189.

1187 + 1188 + 1189 = 3564

We know our answer is correct because 1187 + 1188 + 1189 equals 3564 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 3565?
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