What three consecutive integers have a sum of 3726?

Here we will use algebra to find three consecutive integers whose sum is 3726. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 3726. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 3726

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 3726
3X + 3 = 3726

3X + 3 - 3 = 3726 - 3
3X = 3723

3X/3 = 3723/3
X = 1241

Which means that the first number is 1241, the second number is 1241 + 1 and the third number is 1241 + 2. Therefore, three consecutive integers that add up to 3726 are 1241, 1242, and 1243.

1241 + 1242 + 1243 = 3726

We know our answer is correct because 1241 + 1242 + 1243 equals 3726 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 3727?
Here is the next algebra problem we solved.