What three consecutive integers have a sum of 3771?

Here we will use algebra to find three consecutive integers whose sum is 3771. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 3771. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 3771

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 3771
3X + 3 = 3771

3X + 3 - 3 = 3771 - 3
3X = 3768

3X/3 = 3768/3
X = 1256

Which means that the first number is 1256, the second number is 1256 + 1 and the third number is 1256 + 2. Therefore, three consecutive integers that add up to 3771 are 1256, 1257, and 1258.

1256 + 1257 + 1258 = 3771

We know our answer is correct because 1256 + 1257 + 1258 equals 3771 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 3772?
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