What three consecutive integers have a sum of 3849?

Here we will use algebra to find three consecutive integers whose sum is 3849. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 3849. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 3849

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 3849
3X + 3 = 3849

3X + 3 - 3 = 3849 - 3
3X = 3846

3X/3 = 3846/3
X = 1282

Which means that the first number is 1282, the second number is 1282 + 1 and the third number is 1282 + 2. Therefore, three consecutive integers that add up to 3849 are 1282, 1283, and 1284.

1282 + 1283 + 1284 = 3849

We know our answer is correct because 1282 + 1283 + 1284 equals 3849 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 3850?
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