What three consecutive integers have a sum of 3876?

Here we will use algebra to find three consecutive integers whose sum is 3876. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 3876. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 3876

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 3876
3X + 3 = 3876

3X + 3 - 3 = 3876 - 3
3X = 3873

3X/3 = 3873/3
X = 1291

Which means that the first number is 1291, the second number is 1291 + 1 and the third number is 1291 + 2. Therefore, three consecutive integers that add up to 3876 are 1291, 1292, and 1293.

1291 + 1292 + 1293 = 3876

We know our answer is correct because 1291 + 1292 + 1293 equals 3876 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 3877?
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