What three consecutive integers have a sum of 396?

Here we will use algebra to find three consecutive integers whose sum is 396. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 396. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 396

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 396
3X + 3 = 396

3X + 3 - 3 = 396 - 3
3X = 393

3X/3 = 393/3
X = 131

Which means that the first number is 131, the second number is 131 + 1 and the third number is 131 + 2. Therefore, three consecutive integers that add up to 396 are 131, 132, and 133.

131 + 132 + 133 = 396

We know our answer is correct because 131 + 132 + 133 equals 396 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 397?
Here is the next algebra problem we solved.