What three consecutive integers have a sum of 4089?

Here we will use algebra to find three consecutive integers whose sum is 4089. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 4089. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 4089

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 4089
3X + 3 = 4089

3X + 3 - 3 = 4089 - 3
3X = 4086

3X/3 = 4086/3
X = 1362

Which means that the first number is 1362, the second number is 1362 + 1 and the third number is 1362 + 2. Therefore, three consecutive integers that add up to 4089 are 1362, 1363, and 1364.

1362 + 1363 + 1364 = 4089

We know our answer is correct because 1362 + 1363 + 1364 equals 4089 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 4090?
Here is the next algebra problem we solved.