What three consecutive integers have a sum of 4161?

Here we will use algebra to find three consecutive integers whose sum is 4161. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 4161. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 4161

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 4161
3X + 3 = 4161

3X + 3 - 3 = 4161 - 3
3X = 4158

3X/3 = 4158/3
X = 1386

Which means that the first number is 1386, the second number is 1386 + 1 and the third number is 1386 + 2. Therefore, three consecutive integers that add up to 4161 are 1386, 1387, and 1388.

1386 + 1387 + 1388 = 4161

We know our answer is correct because 1386 + 1387 + 1388 equals 4161 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 4162?
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