What three consecutive integers have a sum of 4335?

Here we will use algebra to find three consecutive integers whose sum is 4335. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 4335. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 4335

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 4335
3X + 3 = 4335

3X + 3 - 3 = 4335 - 3
3X = 4332

3X/3 = 4332/3
X = 1444

Which means that the first number is 1444, the second number is 1444 + 1 and the third number is 1444 + 2. Therefore, three consecutive integers that add up to 4335 are 1444, 1445, and 1446.

1444 + 1445 + 1446 = 4335

We know our answer is correct because 1444 + 1445 + 1446 equals 4335 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 4336?
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