What three consecutive integers have a sum of 4599?

Here we will use algebra to find three consecutive integers whose sum is 4599. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 4599. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 4599

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 4599
3X + 3 = 4599

3X + 3 - 3 = 4599 - 3
3X = 4596

3X/3 = 4596/3
X = 1532

Which means that the first number is 1532, the second number is 1532 + 1 and the third number is 1532 + 2. Therefore, three consecutive integers that add up to 4599 are 1532, 1533, and 1534.

1532 + 1533 + 1534 = 4599

We know our answer is correct because 1532 + 1533 + 1534 equals 4599 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 4600?
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