What three consecutive integers have a sum of 4884?

Here we will use algebra to find three consecutive integers whose sum is 4884. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 4884. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 4884

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 4884
3X + 3 = 4884

3X + 3 - 3 = 4884 - 3
3X = 4881

3X/3 = 4881/3
X = 1627

Which means that the first number is 1627, the second number is 1627 + 1 and the third number is 1627 + 2. Therefore, three consecutive integers that add up to 4884 are 1627, 1628, and 1629.

1627 + 1628 + 1629 = 4884

We know our answer is correct because 1627 + 1628 + 1629 equals 4884 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 4885?
Here is the next algebra problem we solved.