What three consecutive integers have a sum of 4890?

Here we will use algebra to find three consecutive integers whose sum is 4890. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 4890. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 4890

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 4890
3X + 3 = 4890

3X + 3 - 3 = 4890 - 3
3X = 4887

3X/3 = 4887/3
X = 1629

Which means that the first number is 1629, the second number is 1629 + 1 and the third number is 1629 + 2. Therefore, three consecutive integers that add up to 4890 are 1629, 1630, and 1631.

1629 + 1630 + 1631 = 4890

We know our answer is correct because 1629 + 1630 + 1631 equals 4890 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 4891?
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