What three consecutive integers have a sum of 4932?

Here we will use algebra to find three consecutive integers whose sum is 4932. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 4932. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 4932

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 4932
3X + 3 = 4932

3X + 3 - 3 = 4932 - 3
3X = 4929

3X/3 = 4929/3
X = 1643

Which means that the first number is 1643, the second number is 1643 + 1 and the third number is 1643 + 2. Therefore, three consecutive integers that add up to 4932 are 1643, 1644, and 1645.

1643 + 1644 + 1645 = 4932

We know our answer is correct because 1643 + 1644 + 1645 equals 4932 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 4933?
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