What three consecutive integers have a sum of 4944?

Here we will use algebra to find three consecutive integers whose sum is 4944. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 4944. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 4944

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 4944
3X + 3 = 4944

3X + 3 - 3 = 4944 - 3
3X = 4941

3X/3 = 4941/3
X = 1647

Which means that the first number is 1647, the second number is 1647 + 1 and the third number is 1647 + 2. Therefore, three consecutive integers that add up to 4944 are 1647, 1648, and 1649.

1647 + 1648 + 1649 = 4944

We know our answer is correct because 1647 + 1648 + 1649 equals 4944 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 4945?
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