What three consecutive integers have a sum of 4962?

Here we will use algebra to find three consecutive integers whose sum is 4962. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 4962. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 4962

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 4962
3X + 3 = 4962

3X + 3 - 3 = 4962 - 3
3X = 4959

3X/3 = 4959/3
X = 1653

Which means that the first number is 1653, the second number is 1653 + 1 and the third number is 1653 + 2. Therefore, three consecutive integers that add up to 4962 are 1653, 1654, and 1655.

1653 + 1654 + 1655 = 4962

We know our answer is correct because 1653 + 1654 + 1655 equals 4962 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 4963?
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