
Here we will use algebra to find three consecutive integers whose sum is 5016. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 5016. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 5016
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 5016
3X + 3 = 5016
3X + 3 - 3 = 5016 - 3
3X = 5013
3X/3 = 5013/3
X = 1671
Which means that the first number is 1671, the second number is 1671 + 1 and the third number is 1671 + 2. Therefore, three consecutive integers that add up to 5016 are 1671, 1672, and 1673.
1671 + 1672 + 1673 = 5016
We know our answer is correct because 1671 + 1672 + 1673 equals 5016 as displayed above.
Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.
What three consecutive integers have a sum of 5017?
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