What three consecutive integers have a sum of 5133?




Here we will use algebra to find three consecutive integers whose sum is 5133. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 5133. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 5133


To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 5133
3X + 3 = 5133

3X + 3 - 3 = 5133 - 3
3X = 5130

3X/3 = 5130/3
X = 1710

Which means that the first number is 1710, the second number is 1710 + 1 and the third number is 1710 + 2. Therefore, three consecutive integers that add up to 5133 are 1710, 1711, and 1712.

1710 + 1711 + 1712 = 5133

We know our answer is correct because 1710 + 1711 + 1712 equals 5133 as displayed above.


Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.




What three consecutive integers have a sum of 5134?
Here is the next algebra problem we solved.




Copyright  |   Privacy Policy  |   Disclaimer  |   Contact