What three consecutive integers have a sum of 5142?

Here we will use algebra to find three consecutive integers whose sum is 5142. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 5142. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 5142

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 5142
3X + 3 = 5142

3X + 3 - 3 = 5142 - 3
3X = 5139

3X/3 = 5139/3
X = 1713

Which means that the first number is 1713, the second number is 1713 + 1 and the third number is 1713 + 2. Therefore, three consecutive integers that add up to 5142 are 1713, 1714, and 1715.

1713 + 1714 + 1715 = 5142

We know our answer is correct because 1713 + 1714 + 1715 equals 5142 as displayed above.

Three Consecutive Integers
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What three consecutive integers have a sum of 5143?
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