What three consecutive integers have a sum of 5445?

Here we will use algebra to find three consecutive integers whose sum is 5445. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 5445. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 5445

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 5445
3X + 3 = 5445

3X + 3 - 3 = 5445 - 3
3X = 5442

3X/3 = 5442/3
X = 1814

Which means that the first number is 1814, the second number is 1814 + 1 and the third number is 1814 + 2. Therefore, three consecutive integers that add up to 5445 are 1814, 1815, and 1816.

1814 + 1815 + 1816 = 5445

We know our answer is correct because 1814 + 1815 + 1816 equals 5445 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 5446?
Here is the next algebra problem we solved.