What three consecutive integers have a sum of 5877?

Here we will use algebra to find three consecutive integers whose sum is 5877. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 5877. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 5877

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 5877
3X + 3 = 5877

3X + 3 - 3 = 5877 - 3
3X = 5874

3X/3 = 5874/3
X = 1958

Which means that the first number is 1958, the second number is 1958 + 1 and the third number is 1958 + 2. Therefore, three consecutive integers that add up to 5877 are 1958, 1959, and 1960.

1958 + 1959 + 1960 = 5877

We know our answer is correct because 1958 + 1959 + 1960 equals 5877 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

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