What three consecutive integers have a sum of 5919?

Here we will use algebra to find three consecutive integers whose sum is 5919. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 5919. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 5919

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 5919
3X + 3 = 5919

3X + 3 - 3 = 5919 - 3
3X = 5916

3X/3 = 5916/3
X = 1972

Which means that the first number is 1972, the second number is 1972 + 1 and the third number is 1972 + 2. Therefore, three consecutive integers that add up to 5919 are 1972, 1973, and 1974.

1972 + 1973 + 1974 = 5919

We know our answer is correct because 1972 + 1973 + 1974 equals 5919 as displayed above.

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 5920?
Here is the next algebra problem we solved.