What three consecutive integers have a sum of 6004?

Here we will use algebra to find three consecutive integers whose sum is 6004. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 6004. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 6004

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 6004
3X + 3 = 6004

3X + 3 - 3 = 6004 - 3
3X = 6001

3X/3 = 6001/3
X = 2000 1/3

Since 2000 1/3 is not an integer, there is no true answer to this problem.

However, there are three numbers that add up to 6004. The first number is (2000 1/3), the second number is (2000 1/3) + 1, and the third number is (2000 1/3) + 2. Therefore, we could make this the answer to "Three consecutive numbers that add up to 6004 are?":

2000 1/3 + 2001 1/3 + 2002 1/3 = 6004

Three Consecutive Integers
Enter another number below to find what three consecutive integers add up to its sum.

What three consecutive integers have a sum of 6005?
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