What three consecutive integers have a sum of 6291?




Here we will use algebra to find three consecutive integers whose sum is 6291. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 6291. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 6291


To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 6291
3X + 3 = 6291

3X + 3 - 3 = 6291 - 3
3X = 6288

3X/3 = 6288/3
X = 2096

Which means that the first number is 2096, the second number is 2096 + 1 and the third number is 2096 + 2. Therefore, three consecutive integers that add up to 6291 are 2096, 2097, and 2098.

2096 + 2097 + 2098 = 6291

We know our answer is correct because 2096 + 2097 + 2098 equals 6291 as displayed above.


Three Consecutive Integers
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What three consecutive integers have a sum of 6292?
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